TeXes Science Test 2025 – 400 Free Practice Questions to Pass the Exam

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How many grams of Na2SO4 are required to prepare a 10 dm³ of an 8% solution?

750 g

860 g

To determine the correct amount of sodium sulfate (Na2SO4) required to prepare a 10 dm³ solution at an 8% concentration, it's essential to understand what an 8% solution means. An 8% solution indicates that there are 8 grams of solute (in this case, Na2SO4) for every 100 mL of solution.

First, we need to convert the volume of the solution from dm³ to mL because the percentage is typically referenced per 100 mL of solution. Since 1 dm³ is equivalent to 1000 mL, 10 dm³ is equal to 10,000 mL.

Next, we calculate how much Na2SO4 is needed for the entire volume of 10,000 mL. To find the mass of Na2SO4 in an 8% solution:

1. Set up the equation based on the percentage:

- For every 100 mL, there are 8 grams of Na2SO4.

- Therefore, in 10,000 mL (which is 100 times 100 mL), the amount of Na2SO4 needed would be:

\[

8 \text

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1000 g

1200 g

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